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0.06x^2+36x-440=0
a = 0.06; b = 36; c = -440;
Δ = b2-4ac
Δ = 362-4·0.06·(-440)
Δ = 1401.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-\sqrt{1401.6}}{2*0.06}=\frac{-36-\sqrt{1401.6}}{0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+\sqrt{1401.6}}{2*0.06}=\frac{-36+\sqrt{1401.6}}{0.12} $
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